GMAS 6th Grade Mathematics Practice Test

To find the distance between two points, use the horizontal and vertical differences as the legs of a right triangle. From (1, 2) to (4, 6), the horizontal change is 4 − 1 = 3 and the vertical change is 6 − 2 = 4. The distance is the hypotenuse: sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5. This is a 3-4-5 triangle, a common simple distance case. The distance between the points is 5.